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12.5x^2-60x-12.5=0
a = 12.5; b = -60; c = -12.5;
Δ = b2-4ac
Δ = -602-4·12.5·(-12.5)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4225}=65$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-65}{2*12.5}=\frac{-5}{25} =-1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+65}{2*12.5}=\frac{125}{25} =5 $
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